You see that so the singular values are and .
Solving when .
First, you know that will have a solution only if is a multiple of .
In the graphic you can spot that .
Since , you know that is one solution to .
Second, you know that changing the amount of in does not affect .
So is a solution for every value of .
The general solution to is .
(Q29) From the picture you can see that and and .
(Q30) In terms of and , give the general solution to .
Copyright © 2007 Todd Will
Created by Mathematica (April 14, 2007)